7^(3-2x)/7^(7-5x)=49^(3x-14)

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Solution for 7^(3-2x)/7^(7-5x)=49^(3x-14) equation: 



7^(3-2x)/7^(7-5x)=49^(3x-14)

We move all terms to the left:

7^(3-2x)/7^(7-5x)-(49^(3x-14))=0



Domain of the equation: 7^(7-5x)!=0

x∈R



We add all the numbers together, and all the variables

7^(-2x+3)/7^(-5x+7)-(49^(3x-14))=0

We multiply all the terms by the denominator


7^(-2x+3)-((49^(3x-14)))*7^(-5x+7)=0



We calculate terms in parentheses: -((49^(3x-14)))*7^(-5x+7), so:

(49^(3x-14)))*7^(-5x+7

We add all the numbers together, and all the variables

-5x+(49^(3x-14)))*7^(+7

Back to the equation:

-(-5x+(49^(3x-14)))*7^(+7)



We add all the numbers together, and all the variables

7^(-2x+3)-(-5x+(49^(3x-14)))*7^7=0

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